Ideal gas law
For most gases near everyday conditions, pressure, volume, amount and absolute temperature are tied by one equation:
pV = nRT
- p
- absolute pressure
- Pa
- V
- volume
- m³
- n
- amount of gas
- mol
- R
- molar gas constant, 8.314
- J/(mol·K)
- T
- absolute temperature
- K
- m
- mass
- kg
- Rs
- specific gas constant, R/M
- J/(kg·K)
- M
- molar mass
- kg/mol
- ρ
- density
- kg/m³
| T in kelvin | 293.15 K |
| nRT | 2,440 J |
| p = nRT/V | 102 kPa |
Worked example
Uses the values in Fig. 1.1-1. Change them and the working updates.
Given
- namount of gas1 mol
- Ttemperature20 °C
- Vvolume24 L
Find
The pressure p of the gas.
Solution
T = 20 + 273.15 = 293.15 K
p = nRT/V
= 1 mol × 8.314 J/(mol·K) × 293.15 K / 0.024 m³
= 1.02 × 10⁵ Pa
Answer
p = 102 kPa
That is 1.02 bar, or 1 times standard atmospheric pressure (101.325 kPa).
Related forms
For dry air, Rs ≈ 287 J/(kg·K).
-
Per unit mass
pV = mRsTRs = RM
-
Fixed amount, two states
p1V1T1 = p2V2T2
-
Density
ρ = pRsT
Assumptions
- The molecules take up negligible volume and do not attract each other.
- This holds well for air and most gases near room conditions, and less well at high pressure or close to condensing.
- Pressure and temperature are absolute: add 273.15 to °C, and use absolute rather than gauge pressure.
- The gas is in equilibrium, with one pressure and temperature throughout.
Derivation
Three experimental laws each hold two quantities fixed and relate the other two.
- Boyle: at fixed n and T,
pVis constant. - Charles: at fixed n and p,
V ∝ T. - Avogadro: at fixed p and T,
V ∝ n. - Together,
pV ∝ nT. The constant is the same for every ideal gas,R = 8.314 J/(mol·K), sopV = nRT.
Kinetic theory gives the same result from molecules bouncing off the walls: pressure comes from their impacts, and temperature measures their mean kinetic energy.